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NEW QUESTION: 1

A. Option B
B. Option C
C. Option D
D. Option A
Answer: A

NEW QUESTION: 2
Refer to the exhibit.

Your customer sent you this debug output, captured on a Cisco IOS router (router A), to troubleshoot a problem where all H.323 calls that originate from another Cisco IOS router (router B) are being dropped almost immediately after arriving at router A.
What is the reason for these disconnected calls?
A. Calls were rejected by router A because it received an admission reject from its gatekeeper because of toll fraud suspicion.
B. Calls were rejected because the called number was denied on a configured class of restriction list on router A.
C. Calls were unsuccessful because the router B IP address was not found in the trusted source IP address list on router A.
D. Calls were unsuccessful because of internal, memory-related problems on router A.
E. Calls were rejected because the VoIP dial peer 1002 was not operational.
Answer: C

NEW QUESTION: 3
Exhibit

Examine the data in the EMPLOYEES and DEPARTMENTS tables.
You want to retrieve all employees' last names, along with their manager's last names and their department names. Which query would you use?
A. SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
B. SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGT OUTER JOIN departments d ON (e.department_id = d.department_id);
C. SELECT last_name, manager_id, department_name
FROM employees e
FULL OUTER JOIN departments d ON (e.department_id = d.department_id);
D. SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)
E. SELECT last_name, manager_id, department_name
FROM employees e
JOIN departments d ON (e.department_id = d.department_id) ;
F. SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
Answer: F