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NEW QUESTION: 1
Which two tasks can be performed on an external table? (Choose two.)
A. creating a view
B. partitioning the table
C. updating the table by using an UPDATE statement
D. creating a public synonym
E. creating an invisible index
Answer: A,D
Explanation:
Explanation
http://docs.oracle.com/cd/B28359_01/server.111/b28310/tables013.htm#ADMIN01507 You can, for example select, join, or sort external table data. You can also create views and synonyms for external tables. However, no DML operations (UPDATE, INSERT, or DELETE) are possible, and no indexes can be created, on external tables.

NEW QUESTION: 2
On your Oracle 12c database, you invoked SQL *Loader to load data into the EMPLOYEES table in the HR schema by issuing the following command:
$> sqlldr hr/hr@pdb table=employees
Which two statements are true regarding the command?
A. It succeeds with default settings if the EMPLOYEES table belonging to HR is already defined in the database.
B. It fails because no SQL *Loader data file location is specified.
C. It fails because no SQL *Loader control file location is specified.
D. It fails if the HR user does not have the CREATE ANY DIRECTORY privilege.
Answer: A,D
Explanation:
*SQL*Loader is invoked when you specify the sqlldr command and, optionally, parameters that establish session characteristics.

NEW QUESTION: 3
What term describes the effect of increasing the intensity of an RF wave with an antenna by focusing the energy in a specific direction?
A. Active Amplification
B. Beam Compression
C. Distributed Radiation
D. RF Flooding
E. Passive Gain
Answer: E

NEW QUESTION: 4
Refer to the exhibit. EIGRP has been configured on all routers in the network. The command metric weights 0 0 1 0 0 has been added to the EIGRP process so that only the delay metric is used in the path calculations. Which router will R1 select as the successor and feasible successor for Network A?

A. R2 becomes the successor and will be placed in the routing table. No feasible successor will be selected as the reported distance from R4 is lower than the feasible distance.
B. R2 becomes the successor and will be placed in the routing table. R4 becomes the feasible successor for Network A.
C. R4 becomes the successor for Network A and will be included in the routing table. No feasible successor will be selected as the advertised distance from R2 is higher than the feasible distance.
D. R4 becomes the successor for Network A and will be placed in the routing table. R2 becomes the feasible successor for Network A.
Answer: C
Explanation:
The point of the question is DUAL of EIGRP. FD=5+10+5=20 R4 is successor No FS, because no other router's AD is lower the FD