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NEW QUESTION: 1
A security administrator has deployed all laptops with Self Encrypting Drives (SED) and enforces key encryption. Which of the following represents the greatest threat to maintaining data confidentiality with these devices?
A. Laptops that are placed in a sleep mode allow full data access when powered back on.
B. A malicious employee can gain the SED encryption keys through software extraction allowing access to other laptops.
C. If the laptop does not use a Secure Boot BIOS, the SED hardware is not enabled allowing full data access.
D. Full data access can be obtained by connecting the drive to a SATA or USB adapter bypassing the SED hardware.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Hardware-based encryption when built into the drive is transparent to the user. The drive except for bootup authentication operates just like any drive with no degradation in performance. When the computer is started up, the user is prompted to enter a password to allow the system to boot and allow access to the encrypted drive.
When a laptop is placed into sleep mode (also known as standby mode), the computer is placed into a low power mode. In sleep mode, the computer is not fully shut down. The screen is turned off, the hard disks are turned off and the CPU is throttled down to its lowest power state. However, the computer state is maintained in memory (RAM).
Most computers can be 'woken' from sleep mode by pressing any key on the keyboard or pressing the power button. The computer can be configured to require a password on wake up, but if a password is not required, the computer will wake up and be logged in as it was at the time of going into sleep mode. This would enable full access to the data stored on the disks.

NEW QUESTION: 2

A. Option B
B. Option D
C. Option A
D. Option C
Answer: A

NEW QUESTION: 3
A VSM is actually a virtual machine that requires how many vNICs for functioning?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: E

NEW QUESTION: 4
Using the rates of z1= 3.00%,1f1= 3.60%,1f2= 3.92%,1f3= 5.15%, compute the forward discount factor for period two.
A. 0.98377
B. 0.9678
C. 1.03327
Answer: B
Explanation:
1/(1.015)(1.018) = 1/1.03327 = 0.9678