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NEW QUESTION: 1
What action(s) can an administrator take on an existing file system from its Properties page?
A. Assigned HAS Server can be deleted
B. Different Pool can be selected
C. Format can be changed to UFS32
D. Size can be expanded or shrunk
Answer: A

NEW QUESTION: 2
You maintain a SQL Server database that is used by a retailer to track sales and salespeople. The database includes two tables and two triggers that is defined by the following Transact-SQL statements:

During days with a large sales volume, some new sales transaction fail and report the following error:
Arithmetic overflow error converting expression to data type int.
You need to ensure that the two triggers are applied once per sale, and that they do not interfere with each other.
How should you complete the relevant Transact-SQL statement? To answer, drag the appropriate Transact-SQL segments to the correct location or locations. Each Transact-SQL segment may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.

Answer:
Explanation:

Explanation

Box 1: OFF
Box 2: 0
Only direct recursion of AFTER triggers is prevented when the RECURSIVE_TRIGGERS database option is set to OFF. To disable indirect recursion of AFTER triggers, also set the nested triggers server option to 0.
Note: Both DML and DDL triggers are nested whena trigger performs an action that initiates another trigger.
These actions can initiate other triggers, and so on. DML and DDL triggers can be nested up to 32 levels. You can control whether AFTER triggers can be nested through the nested triggers server configuration option.
If nested triggers are allowed and a trigger in the chain starts an infinite loop, the nesting level is exceeded and the trigger terminates.
References:https://msdn.microsoft.com/en-us/library/ms190739.aspx

NEW QUESTION: 3
Refer to the exhibit.

In this VLSM addressing scheme, what summary address would be sent from router A?
A. 172.32.0.0 /16
B. 172.16.0.0 /20
C. 172.16.0.0 /16
D. 172.64.0.0 /16
E. 172.16.0.0 /24
F. 172.32.0.0 /17
Answer: C
Explanation:
Router A receives 3 subnets: 172.16.64.0/18, 172.16.32.0/24 and 172.16.128.0/18.
All these 3 subnets have the same form of 172.16.x.x so our summarized subnet must be also in that form -> Only A, B or .
The smallest subnet mask of these 3 subnets is /18 so our summarized subnet must also have its subnet mask equal or smaller than /18.
-> Only answer A has these 2 conditions ->.