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  • Exam Code: CTFL_Syll2018
  • Exam Name: ISTQB Certified Tester Foundation Level (Syllabus 2018)
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Version: V17.95
  • Q & A: 400 Questions and Answers
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NEW QUESTION: 1
トポロジ図に示されているように、部分的な構成を持ち、RouterCに接続されたマルチレイヤーSwitchCの構成を担当しました。
ホストH1およびH2がサーバーS1に正常にpingできるように、SwitchCを構成する必要があります。また、SwitchCはサーバーS1をpingできる必要があります。
管理上の制限と要件のため、VLANを追加/削除したり、トランクリンクを作成したりしないでください。
会社のポリシーでは、静的ルーティングまたはデフォルトルーティングの使用が禁止されています。すべてのルートは、EIGRP 65010ルーティングプロトコルを介して学習する必要があります。
RouteCにアクセスできません。 RouterCが正しく構成されています。 RouterCでトランキングが設定されていません。
可能な場合、ルーテッドインターフェイスはサブネット上の最も低いホストを使用する必要があります。このソリューションを実装するには、次のサブネットを使用できます。
-10.10.10.0/24
-190.200.250.32/27
-190.200.250.64/27
ホストH1とH2は、正しいIPアドレスとデフォルトゲートウェイで構成されています。
SwitchCは、Ciscoをイネーブルパスワードとして使用します。
ルーティングは、図に示されている特定のサブネットに対してのみ有効にする必要があります。
注:管理上の制限と要件のため、VLANを追加または削除したり、VLANポートの割り当てを変更したり、トランクを作成したりしないでください。会社のポリシーでは、静的ルーティングまたはデフォルトルーティングの使用が禁止されています。すべてのルートは、EIGRPルーティングプロトコルを介して学習する必要があります。




Answer:
Explanation:
See the explanation for step by step solution:
Explanation
There are two ways to configure interVLAN routing in this case:
+ Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch. Trunking must be established between RouterC and SwitchC.+ Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer 3 switch (which supports ip routing function as a router). No trunking requires.
The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3 switch with SVIs for interVLAN routing.
We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways.
C:\>ipconfig
We will get the default gateways as follows:
Host1:+ Default gateway: 190.200.250.33
Host2:+ Default gateway: 190.200.250.65
Now we have enough information to configure SwitchC (notice the EIGRP AS in this case is 650) Note: VLAN2 and VLAN3 were created and gi0/10, gi0/11 interfaces were configured as access ports so we don't need to configure them in this sim.
SwitchC# configure terminalSwitchC(config)# int gi0/1SwitchC(config-if)#no switchport -> without using this command, the simulator does not let you assign IP address on Gi0/1 interface.SwitchC(config-if)# ip address 10.10.10.2 255.255.255.0 ->RouterC has used IP 10.10.10.1 so this is the lowest usable IP address.SwitchC(config-if)# no shutdownSwitchC(config-if)# exitSwitchC(config)# int vlan 2 SwitchC(config-if)# ip address 190.200.250.33 255.255.255.224SwitchC(config-if)# no shutdown SwitchC(config-if)# int vlan 3SwitchC(config-if)# ip address 190.200.250.65 255.255.255.224 SwitchC(config-if)# no shutdown ip routing (Notice: MLS will not work without this command)SwitchC(config)# SwitchC(config-router)# network 10.10.10.0
0.0.0.255SwitchC(config-router)# SwitchC(config-router)# network
190.200.250.64 0.0.0.31
NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the exam , also don't modify/delete any port just do the above configuration. Also some reports said the "no auto-summary" command can't be used in the simulator, in fact it is not necessary because the network 190.200.0.0/16 is not used anywhere else in this topology.
In order to complete the lab, you should expect the ping to SERVER to succeed from the MLS , and from the PCs as well.
Also make sure you use the correct EIGRP AS number (in the configuration above it is 650 but it will change when you take the exam) but we are not allowed to access RouterC so the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS number, no neighbor relationship is formed between RouterC and SwitchC.
In fact, we are pretty sure instead of using two commands "network 190.200.250.32 0.0.0.31 and "network
190.200.250.64 0.0.0.31 we can use one simple command "network 190.200.0.0 because it is the nature of distance vector routing protocol like EIGRP: only major networks need to be advertised; even without "no auto-summary" command the network still works correctly. But in the exam the sim is just a flash based simulator so we should use two above commands, just for sure. But after finishing the configuration, we can use "show run" command to verify, only the summarized network 190.200.0.0 is shown.

NEW QUESTION: 2
バケット所有者は、別のアカウントのIAMユーザーが自分のバケット内のオブジェクトをアップロードまたはアクセスすることを許可しています。 アカウントAのIAMユーザーは、アカウントのIAMユーザーによって作成されたオブジェクトにアクセスしようとしています
B.何
  このシナリオではどうなりますか?
A. 1つのアカウントのIAMユーザーが他のIAMユーザーのオブジェクトにアクセスすることはできません
B. アクセス権の競合によりS3がエラーを出すため、バケットポリシーが作成されない場合があります
C. 複数のIAMユーザーに許可を与えることはできません
D. AWS S3は、アカウントAの所有者、バケット所有者、およびIAMユーザーBからオブジェクトに付与された適切な権利を確認します
Answer: D
Explanation:
If a IAM user is trying to perform some action on an object belonging to another AWS user's bucket, S3 will verify whether the owner of the IAM user has given sufficient permission to him. It also verifies the policy for the bucket as well as the policy defined by the object owner.
http://docs.aws.amazon.com/AmazonS3/latest/dev/access-control-auth-workflow-object- operation.html

NEW QUESTION: 3
DRAG DROP
You develop an HTML5 webpage. You have the following HTML markup:

You need to update the content of the DIV element when the mouse hovers over an image and when the mouse coordinates change.
How should you complete the relevant code? (To answer, drag the appropriate code segment to the correct location or locations in the answer area. Use only code segments that apply.) Select and Place:

Answer:
Explanation:

Explanation/Reference:
Explanation:
* addEventLister mousemove
Use the element.addEventListener() method to attach an event handler to a specified element.
onmousemove : Fires when the mouse pointer is moving while it is over an element
* The clientX property returns the horizontal coordinate (according to the client area) of the mouse pointer when a mouse event was triggered.
Example:
Output the coordinates of the mouse pointer when an mouse event has occurred:
var x = event.clientX; // Get the horizontal coordinate
var y = event.clientY; // Get the vertical coordinate
var coor = "X coords: " + x + ", Y coords: " + y;
The result of coor could be:
X coords: 142, Y coords: 99
Reference: HTML DOM addEventListener() Method; onmousemove Event; MouseEvent clientX Property

NEW QUESTION: 4
A SysOps Administrator manages an application that stores object metadata in Amazon S3. There is a requirement to have S3 server-side encryption enabled on all new objects in the bucket.
How can the Administrator ensure that all new objects added to the bucket satisfy this requirement?
A. Create an S3 lifecycle rule to automatically encrypt all new objects
B. Enable default bucket encryption to ensure that all new objects are encrypted
C. Use put-object-ac1 to allow objects to be encrypted with S3 server-side encryption
D. Apply the authorization heeder to S3 requests for S3 server-side encryption.
Answer: B

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