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NEW QUESTION: 1
どの2つがGETVPNの機能ですがDMVPNとFlexVPNは違いますか？ （2つ選んでください。）
A. オーバーレイルーティングプロトコルは不要
B. パブリックまたはプライベートWAN経由で使用するための設計
C. 外部ヘッダにIPプロトコルを保存
D. ESPまたはAHの使用を有効にしました
E. スケーラブルリプレイチェックを可能にするシーケンス番号
F. すべての暗号化トラフィックに対して1つのIPsec SA
Answer: A,F

NEW QUESTION: 2
Which three types of ACL would you use to secure traffic on the network? (Choose three.)
A. packets
B. dynamic
C. firewalls
D. IPS
E. reflexive
F. VLAN
Answer: B,E,F

NEW QUESTION: 3
Refer to the exhibit. Customer is planning to deploy a clustering over the WAN UCM topology with 2 subscribers at site 1 and 2 subscribers at site 2.
How much bandwidth would be required between site 1 and site 2 to for database replication?

A. 7.772 Mbps
B. 4.632 Mbps
C. 1.544 Mbps
D. 6.176 Mbps
E. 3.088 Mbps
Answer: B
Explanation:
Consider two sites, Site 1 and Site 2, with Unified CM clustered over the WAN across these two sites that are 80 msec round-trip time apart. Site 1 has one publisher, one combined TFTP and music on hold (MoH) server, and two Unified CM subscriber servers. Site 2 has one TFTP/MoH server and two Unified CM subscriber servers. Site 1 has 5000 phones, each having one DN; and Site 2 has 5000 phones, each having one DN. During the busy hour, 2500 phones in Site 1 call
2500 phones in Site 2, each at 3 BHCA. During that same busy hour, 2500 phones in Site 2 also call 2500 phones in Site 1, each at 3 BHCA. In this case:
Total BHCA during the busy hour = 2500*3 + 2500*3 = 15,000
Total bandwidth required between the sites = Total ICCS bandwidth + Total database bandwidth Because total BHCA is 15,000 (greater than 10,000), we can use the formula to calculate:
Total ICCS bandwidth = (15,000/10,000) * (1 + 0.006*80) = 2.22 Mbps
Total database bandwidth = (Number of servers remote to the publisher) * 1.544 = 3 * 1.544 =
4.632 Mbps
http://www.cisco.com/c/en/us/td/docs/voice_ip_comm/cucm/srnd/7x/uc7_0/models.html

NEW QUESTION: 4
During deployment, a network engineer notices that voice traffic is not being tagged correctly as it traverses the network. Which COS to DSCP map must be modified to ensure that voice traffic is treated properly?
A. COS of 6 to DSCP 46
B. COS of 3 to DSCP of 26
C. COS of 5 to DSCP 46
D. COS of 7 to DSCP 48
Answer: C
Explanation:
CoS value 5 is commonly used for VOIP and CoS value 5 should be mapped to DSCP 46. DSCP 46 is defined as being for EF (Expedited Forwarding) traffic flows and is the value usually assigned to all interactive voice and video traffic. This is to keep the uniformity from end-to-end that DSCP EF (mostly for VOICE RTP) is mapped to COS 5.
Note:
+ CoS is a L2 marking contained within an 802.1q tag,. The values for CoS are 0 - 7 + DSCP is a L3 marking and has values 0 - 63 + The default DSCP-to-CoS mapping for CoS 5 is DSCP 40