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NEW QUESTION: 1
What is the value of a pre-implementation Technical Delivery Assessment for a customer?
A. The assessment maximizes customer satisfaction by creating a checklist of actions designed to reduce risk.
B. The assessment is performed by IBM Lab Services to ensure solution design quality.
C. The assessment ensures that system administration requirements are consistent with customer expectations.
D. The assessment creates a report detailing the education and services needed to ensure maximum system performance.
Answer: A

NEW QUESTION: 2
Refer to the exhibit.

Which statement accurately represents the characteristics of the core layer in this design?
A. Partial mesh should be used as long as it is connected to each device by multiple paths.
B. QoS should only be performed only in the core.
C. Load balancing should never be implemented or used.
D. Policy-based traffic control should be implemented to enable prioritization and ensure the best
performance for all time-critical applications.
E. Access lists should be used in the core to perform packet manipulation.
Answer: A
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 3
The Data Encryption Standard (DES) encryption algorithm has which of the following characteristics?
A. 64 bit blocks with a 64 bit total key length
B. 128 bit key with 8 bits used for parity
C. 56 bits of data input results in 56 bits of encrypted output
D. 64 bits of data input results in 56 bits of encrypted output
Answer: A
Explanation:
Explanation/Reference:
DES works with 64 bit blocks of text using a 64 bit key (with 8 bits used for parity, so the effective key length is 56 bits).
Some people are getting the Key Size and the Block Size mixed up. The block size is usually a specific length. For example DES uses block size of 64 bits which results in 64 bits of encrypted data for each block. AES uses a block size of 128 bits, the block size on AES can only be 128 as per the published standard FIPS-197.
A DES key consists of 64 binary digits ("0"s or "1"s) of which 56 bits are randomly generated and used directly by the algorithm. The other 8 bits, which are not used by the algorithm, may be used for error detection. The 8 error detecting bits are set to make the parity of each 8-bit byte of the key odd, i.e., there is an odd number of "1"s in each 8-bit byte1. Authorized users of encrypted computer data must have the key that was used to encipher the data in order to decrypt it.
IN CONTRAST WITH AES
The input and output for the AES algorithm each consist of sequences of 128 bits (digits with values of 0 or
1). These sequences will sometimes be referred to as blocks and the number of bits they contain will be referred to as their length. The Cipher Key for the AES algorithm is a sequence of 128, 192 or 256 bits.
Other input, output and Cipher Key lengths are not permitted by this standard.
The Advanced Encryption Standard (AES) specifies the Rijndael algorithm, a symmetric block cipher that can process data blocks of 128 bits, using cipher keys with lengths of 128, 192, and 256 bits. Rijndael was designed to handle additional block sizes and key lengths, however they are not adopted in the AES standard.
The AES algorithm may be used with the three different key lengths indicated above, and therefore these different "flavors" may be referred to as "AES-128", "AES-192", and "AES-256".
The other answers are not correct because:
"64 bits of data input results in 56 bits of encrypted output" is incorrect because while DES does work with
64 bit block input, it results in 64 bit blocks of encrypted output.
"128 bit key with 8 bits used for parity" is incorrect because DES does not ever use a 128 bit key.
"56 bits of data input results in 56 bits of encrypted output" is incorrect because DES always works with 64 bit blocks of input/output, not 56 bits.
Reference(s) used for this question:
Official ISC2 Guide to the CISSP CBK, Second Edition, page: 336-343
http://csrc.nist.gov/publications/fips/fips197/fips-197.pdf
http://csrc.nist.gov/publications/fips/fips46-3/fips46-3.pdf

NEW QUESTION: 4
With Cisco ASA active/standby failover, what is needed to enable subsecond failover?
A. Enable the stateful failover interface between the primary and secondary Cisco ASA.
B. Use redundant interfaces.
C. Decrease the default number of monitored interfaces to 1.
D. Decrease the default unit failover polltime to 300 msec and the unit failover holdtime to 900 msec.
Answer: D
Explanation:
http://www.cisco.com/en/US/docs/security/asa/asa83/asdm63/configuration_guide/ha_active_stan dby.html
Configuring the Unit and Interface Health Poll Times
The adaptive security appliance sends hello packets out of each data interface to monitor interface health. Theappliance sends hello messages across the failover link to monitor unit health. If the adaptive securityappliance does not receive a hello packet from the corresponding interface on the peer unit for over half of thehold time, then the additional interface testing begins. If a hello packet or a successful test result is not receivedwithin the specified hold time, the interface is marked as failed. Failover occurs if the number of failedinterfaces meets the failover criteria.
Decreasing the poll and hold times enables the adaptive security appliance to detect and respond to interfacefailures more quickly, but may consume more system resources. Increasing the poll and hold times preventsthe adaptive security appliance from failing over on networks with higher latency.