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NEW QUESTION: 1
What is the minimum number of H.225 messages required to establish an H.323 call with bidirectional media?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: E
Explanation:
Explanation/Reference:
Explanation:
A typical H.245 exchange looks similar to below figure
After this exchange of messages, the two endpoints (EP) in this figure would be transmitting audio in each direction. The number of message exchanges is numerous, each has an important purpose, but nonetheless takes time.
For this reason, H.323 version 2 (published in 1998) introduced a concept called Fast Connect, which enables a device to establish bi-directional media flows as part of the H.225.0 call establishment procedures. With Fast Connect, it is possible to establish a call with bi-directional media flowing with no more than two messages, like in figure 3.
Fast Connect is widely supported in the industry. Even so, most devices still implement the complete
H.245 exchange as shown above and perform that message exchange in parallel to other activities, so there is no noticeable delay to the calling or called party.

NEW QUESTION: 2
Your customer asks you to verify the current subnet mask assigned to a remote Avaya G350 Media Gateway Primary Management Interface (PMI). Which two commands identify the information requested? (Choose two.)
A. statuspmi
B. show running-config
C. list configuration media-gateway
D. show interfacevlan (vlan #)
Answer: B,D

NEW QUESTION: 3
Which two statements are true regarding the COUNT function? (Choose two.)
A. COUNT(*) returns the number of rows including duplicate rows and rows containing NULL value in any of the columns
B. COUNT(DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and NULL values in the INV_AMT column
C. The COUNT function can be used only for CHAR, VARCHAR2 and NUMBER data types
D. A SELECT statement using COUNT function with a DISTINCT keyword cannot have a WHERE clause
E. COUNT(cust_id) returns the number of rows including rows with duplicate customer IDs and NULL value in the CUST_ID column
Answer: A,B
Explanation:
Using the COUNT Function
The COUNT function has three formats:
COUNT(*)
COUNT(expr)
COUNT(DISTINCT expr)
COUNT(*) returns the number of rows in a table that satisfy the criteria of the SELECT statement,
including duplicate rows and rows containing null values in any of the columns. If a WHERE
clause is included in the SELECT statement, COUNT(*) returns the number of rows that satisfy the
condition in the WHERE clause.
In contrast,
COUNT(expr) returns the number of non-null values that are in the column identified by expr.
COUNT(DISTINCT expr) returns the number of unique, non-null values that are in the column
identified by expr.