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NEW QUESTION: 1
A conference has been scheduled two hours in advance. When does Cisco Telepresence Management Suite run diagnostics for system tickets that can affect the conference setup?
A. 10 minutes prior to the scheduled start time
B. 5 minute prior to the scheduled start time
C. 15 minutes prior to the scheduled start time
D. 1 minute prior to the scheduled start time
Answer: C
Explanation:
Explanation
https://www.cisco.com/c/dam/en/us/td/docs/telepresence/infrastructure/tms/admin_guide/Cis co-TMS-Admin-Guide-14-6.pdf

NEW QUESTION: 2
Given:

Given the code fragment:

Which two sets of actions, independently, enable the code fragment to print Fit?
A. At line n1 insert: import clothing.*;
At line n2 insert: String color = Shirt.getColor ( ) ;
B. At line n1 no changes required.
At line n2 insert: String color = Shirt.getColor ( ) ;
C. At line n1 insert: import clothing;
At line n2 insert: String color = Shirt.getColor ( ) ;
D. At line n1 insert: import static clothing.Shirt.getcColor;
At line n2 insert: String color = getColor ( ) ;
E. At line n1 insert: import clothing.Shirt ;
At line n2 insert: String color = getColor ( ) ;
Answer: A,D

NEW QUESTION: 3
Which storage protocol allows administrators to reduce the total number of network ports used in the network environment?
A. Network File System
B. Fibre Channel
C. Fibre Channel over Ethernet
D. Virtual SAN
Answer: C
Explanation:
Explanation/Reference:
Explanation:
FCoE: The Fibre Channel traffic is encapsulated into Fibre Channel over Ethernet (FCoE) frames. These FCoE frames are converged with other types of traffic on the Ethernet network. By carrying both Ethernet and Fibre Channel traffic on the same Ethernet link, the utilization of the physical infrastructure has greatly increased. FCoE also reduces the total number of network ports and cabling.

NEW QUESTION: 4
Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
A. The network is not subnetted.
B. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
C. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
D. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
E. The subnet address is 10.16.3.0 255.255.254.0.
Answer: B,D
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are
2.1 through 3.254