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NEW QUESTION: 1
CORRECT TEXT
EIGRP
After adding RTR_2 router, no routing updates are being exchanged between RTR_1 and the new location. All other inter connectivity and internet accesses for the existing locations of the company are working properly.

The task is to identify the fault(s) and correct the router configuration to provide full connectivity between the routers.
Access to the router CLI can be gained by clicking on the appropriate host. All passwords on all routers are Cisco.
IP addresses are listed in the chart below.

RTR_A#show run ! !
interface FastEthernet0/0 ip address 192.168.60.97 255.255.255.240 ! interface FastEthernet0/1 ip address 192.168.60.113 255.255.255.240 ! interface Serial0/0 ip address 192.168.36.14 255.255.255.252 clockrate 64000 ! router eigrp 212 network 192.168.36.0 network 192.168.60.0 no auto-summary ! RTR_A#show ip route 192.168.36.0/30 is subnetted, 1 subnets C 192.168.36.12 is directly connected, Serial 0/0 192.168.60.0/24 is variably subnetted, 5 subnets, 2 masks C 192.168.60.96/28 is directly connected, FastEthernet0/0 C 192.168.60.112/28 is directly connected, FastEthernet0/1 D 192.168.60.128/28 [ 90/21026560 ] via 192.168.36.13, 00:00:57, Serial 0/0 D 192.168.60.144/28 [ 90/21026560 ] via 192.168.36.13, 00:00:57, Serial 0/0 D 192.168.60.24/30 [ 90/21026560 ] via 192.168.36.13, 00:00:57, Serial 0/0 D* 198.0.18.0 [ 90/21026560 ] via 192.168.36.13, 00:00:57, Serial 0/0 ******************************************************************************* RTR_2#show run ! ! interface FastEthernet0/0 ip address 192.168.77.34 255.255.255.252 ! interface FastEthernet0/1 ip address 192.168.60.65 255.255.255.240 ! interface FastEthernet1/0 ip address 192.168.60.81 255.255.255.240 ! ! router eigrp 22 network 192.168.77.0 network 192.168.60.0 no auto-summary ! RTR_2#show ip route 192.168.60.0/28 is variably subnetted, 2 subnets C 192.168.60.80 is directly connected, FastEthernet1/0 C 192.168.60.64 is directly connected, FastEthernet0/1 192.168.77.0/30 is subnetted, 1 subnets C 192.168.77.32 is directly connected, FastEthernet0/0 ********************************************************** RTR_B#show run ! interface FastEthernet0/0 ip address 192.168.60.129 255.255.255.240 ! interface FastEthernet0/1 ip address 192.168.60.145 255.255.255.240 ! interface Serial0/1 ip address 192.168.60.26 255.255.255.252 ! router eigrp 212 network 192.168.60.0 ! RTR_B#show ip route 192.168.60.0/24 is variably subnetted, 5 subnets, 2 masks C 192.168.60.24/30 is directly connected, Serial0/1 C 192.168.60.128/28 is directly connected, FastEthernet0/0 C 192.168.60.144/28 is directly connected, FastEthernet0/1 D 192.168.60.96/28 [ 90/21026560 ] via 192.168.60.25, 00:00:57, Serial 0/1 D 192.168.60.112/28 [ 90/21026560 ] via 192.168.60.25, 00:00:57, Serial 0/1 192.168.36.0/30 is subnetted, 1 subnets D 192.168.36.12 [ 90/21026560 ] via 192.168.60.25, 00:00:57, Serial 0/1 D* 198.0.18.0 [ 90/21026560 ] via 192.168.60.25, 00:00:57, Serial 0/1 ************************************************************************** RTR_1#show run ! ! interface FastEthernet0/0 ip address 192.168.77.33 255.255.255.252
! interface Serial1/0 ip address 198.0.18.6 255.255.255.0 ! ! interface Serial0/0 ip address 192.168.36.13 255.255.255.252 clockrate 64000 ! interface Serial0/1 ip address 192.168.60.25 255.255.255.252 clockrate 64000 ! ! router eigrp 212 network 192.168.36.0 network 192.168.60.0 network 192.168.85.0 network 198.0.18.0 no auto-summary ! ip classless ip default-network 198.0.18.0 ip route 0.0.0.0 0.0.0.0 198.0.18.5 ip http server RTR_1#show ip route 192.168.36.0/30 is subnetted, 1 subnets C 192.168.36.12 is directly connected, Serial 0/0
192.168.60.0/24 is variably subnetted, 5 subnets, 2 masks
C 192.168.60.24/30 is directly connected, Serial0/1
D 192.168.60.128/28 [ 90/21026560 ] via 192.168.60.26, 00:00:57, Serial 0/1
D 192.168.60.144/28 [ 90/21026560 ] via 192.168.60.26, 00:00:57, Serial 0/1
D 192.168.60.96/28 [ 90/21026560 ] via 192.168.36.14, 00:00:57, Serial 0/0
192.168.77.0/30 is subnetted, 1 subnets
C 192.168.77.32 is directly connected, FastEthernet0/0
C 192.0.18.0/24 is directly connected, Serial 1/0
*S 0.0.0.0 via 198.0.18.5
Answer:
Explanation:
2>enable Router2#config t Router2(config)#no router eigrp 22 Router2(config)#router eigrp 212 Router2(config-router)#network 192.16.60.0 Router2(config-router)#network 192.16.77.0 ROUTER1>enable ROUTER1#config t ROUTER1(config)#router eigrp 212 ROUTER1(config-router)#network 192.16.77.0 ROUTER1(config-router)#end ROUTER1#copy run start

NEW QUESTION: 2
You need to debug the user greeting
issue.
What should you use?
A. Azure Application Insights
B. Bot Framework Channel Inspector
C. Bot Framework Emulator
D. Azure Compote Emulator
E. Bot Connector service
Answer: A

NEW QUESTION: 3
Identify the three delivered free-form content types of Profile Management.
A. Languages
B. Career Preferences
C. Accomplishments
D. Honors and Awards
E. Potential
Answer: A,C,D

NEW QUESTION: 4
There are three implementations of CAC. What is wrong about the CAC implementation based on channel utilization?
A. The AP periodically detects the channel utilization of the radio. Once it falls below the new user threshold, it sends a release alarm to allow new users to go online.
B. For the access of the roaming user, check whether the channel utilization has reached the roaming user threshold. If it is reached, the roaming user access request is rejected and an alarm is sent.
C. If the channel utilization reaches the new user threshold after the new user goes online, the access request of other new users is rejected, and an alarm is sent, but the SSID cannot be hidden.
D. When receiving a new user online request, the AP first calculates the channel utilization rate on the current radio. If the new user threshold is not reached, the new user is allowed to go online.
Answer: C