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  • Exam Code: C-S4CWM-2308
  • Exam Name: SAP Certified Application Associate - SAP S/4HANA Cloud, public edition - Warehouse Management
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C-S4CWM-2308
  • Exam Name: SAP Certified Application Associate - SAP S/4HANA Cloud, public edition - Warehouse Management
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C-S4CWM-2308
  • Exam Name: SAP Certified Application Associate - SAP S/4HANA Cloud, public edition - Warehouse Management
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  • Q & A: 400 Questions and Answers
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NEW QUESTION: 1
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
protected:
int y;
public:
int x,z;
A() : x(2), y(2), z(1) { z = x + y; }
A(int a, int b) : x(a), y(b) { z = x + y;}
void Print() { cout << z; }
};
class B : public A {
public:
int y;
B() : A() {}
B(int a, int b) : A(a,b) {}
void Print() { cout << z; }
};
int main () {
A b;
b.Print();
return 0;
}
A. It prints: 3
B. It prints: 4
C. It prints: 0
D. It prints: 2
Answer: B

NEW QUESTION: 2
You need to enable journaling and Legal Hold to ensure your compliance scenario.
Why is this?
A. Because Legal Hold will show you all of the messages, but not the actual recipients at the time the message was sent.
B. Because journaling only stores the data on a single mailbox database, and therefore the performance of searching this mailbox is poor.
C. Journaling only works to external third-party storage, and so eDiscovery searches allow you to query Exchange Server before you query the third-party service.
D. Because Legal Hold only tracks items in Exchange that are not delivered as messages, and journaling keeps a copy of all messages.
Answer: A

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:

The tables include the following records:
Customer_CRMSystem

Customer_HRSystem

Records that contain null values for CustomerCode can be uniquely identified by CustomerName.
You need to display a list of customers that do not appear in the Customer_HRSystem table.
Which Transact-SQL statement should you run?


A. Option G
B. Option B
C. Option F
D. Option C
E. Option D
F. Option H
G. Option E
H. Option A
Answer: E
Explanation:
Explanation
EXCEPT returns distinct rows from the left input query that aren't output by the right input query.
References: https://msdn.microsoft.com/en-us/library/ms188055.aspx

NEW QUESTION: 4
What is the key difference between Business Continuity and Business Continuity Management?
A. They are same concepts used interchangeably
B. None of the above
C. Business Continuity is the capability of the organization whereas Business Continuity Management is the holistic process.
D. Business Continuity is the holistic process whereas Business Continuity Management is the capability of the organization
Answer: C
Explanation:
Definitions:
Business continuity: The capability of the organisation to continue delivery of products or services at acceptable predefined levels following a loss of service.
Business continuity management: A holistic management process that identifies potential threats to an organisation and the impacts to business operations those threats, if realised, might cause. It provides a framework for building organisational resilience with the capability of an effective response that safeguards the interests of its key stakeholders, reputation, brand, and value-creating activities

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