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NEW QUESTION: 1
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
* Students must be ranked based on their average marks.
* If one or more students have the same average, the same rank must be given to these students.
* Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: E
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx

NEW QUESTION: 2
Identify the memory module technology used by the MacBook Air (11-inch, Mid 2013) and MacBook Air (13-inch, Mid 2013).
A. DDR3L
B. DDRPC3
C. PLDDR3
D. LPDDR3
Answer: A

NEW QUESTION: 3



A. router2(config)#ip route 10.89.3.0 255.255.0.0 10.89.16.2
B. router2(config)#ip route 0.0.0.0 0.0.0.0 10.89.16.1
C. router1(config)#ip route 10.89.0.0 255.255.240.0 10.89.16.2
D. router1(config)#ip route 10.89.0.0 255.255.240.0 10.89.16.1
Answer: B