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NEW QUESTION: 1
You need to develop a Transact-SQL statement that meets the following requirements:
- The statement must return a custom error when there are problems updating a table.
- The error number must be value 50555.
- The error severity level must be 14.
- A Microsoft SQL Server alert must be triggered when the error condition occurs.
Which Transact-SQL segment should you use for each requirement? To answer, select the appropriate Transact-SQL segments in the answer area.

Answer:
Explanation:

Explanation

Box 1: TRY...CATCH
The TRY...CATCH Transact-SQL construct implements error handling for Transact-SQL that is similar to the exception handling in the Microsoft Visual C# and Microsoft Visual C++ languages. A group of Transact-SQL statements can be enclosed in a TRY block. If an error occurs in the TRY block, control is passed to another group of statements that is enclosed in a CATCH block.
Box 2: RAISERROR(50555, 14, 1 'The update failed.") WITH LOG
We must use RAISERROR to be able to specify the required severity level of 14, and we should also use the LOG option, which Logs the error in the error log and the application log for the instance of the Microsoft SQL Server Database Engine, as this enable a MS MS SQL SERVER alert to be triggered.
Note: RAISERROR generates an error message and initiates error processing for the session. RAISERROR can either reference a user-defined message stored in the sys.messages catalog view or build a message dynamically. The message is returned as a server error message to the calling application or to an associated CATCH block of a TRY...CATCH construct.

NEW QUESTION: 2
Which two properly implement a Singleton pattern?
A. class Singleton {
private static Singleton instance;
private Singleton () {}
public static synchronized Singleton getInstance() {
if (instance == null) {
instance = new Singleton ();
}
return instance;
}
}
B. class Singleton {
private static Singleton instance = new Singleton();
protected Singleton () {}
public static Singleton getInstance () {
return instance;
}
}
C. enum Singleton {
INSTANCE;
}
D. class Singleton {
Singleton () {}
private static class SingletonHolder {
private static final Singleton INSTANCE = new Singleton ();
}
public static Singleton getInstance () {
return SingletonHolder.INSTANCE; } }
Answer: A,C
Explanation:
A: Here the method for getting the reference to the SingleTon object is correct.
B: The constructor should be private
C: The constructor should be private
Note: Java has several design patterns Singleton Pattern being the most commonly used. Java Singleton pattern belongs to the family of design patterns, that govern the instantiation process. This design pattern proposes that at any time there can only be one instance of a singleton (object) created by the JVM.
The class's default constructor is made private, which prevents the direct instantiation of the object by others (Other Classes). A static modifier is applied to the instance method that returns the object as it then makes this method a class level method that can be accessed without creating an object.
OPTION A == SHOW THE LAZY initialization WITHOUT DOUBLE CHECKED LOCKING TECHNIQUE ,BUT
ITS CORRECT OPTION D == Serialzation and thraead-safety guaranteed and with couple of line of code enum Singleton pattern is best way to create Singleton in Java 5 world.
AND THERE ARE 5 WAY TO CREATE SINGLETON CLASS IN JAVA 1>>LAZY LOADING (initialization) USING SYCHRONIZATION 2>>CLASS LOADING (initialization) USING private static final Singleton instance = new
Singleton(); 3>>USING ENUM 4>>USING STATIC NESTED CLASS
5>>USING STATIC BLOCK
AND MAKE CONSTRUCTOR PRIVATE IN ALL 5 WAY.

NEW QUESTION: 3
데이터 과학자가 다양한 이진 분류 모델을 평가하고 있습니다. 위양성 결과는 비즈니스 관점에서 위양성 결과보다 5 배 더 비쌉니다.
모델은 다음 기준에 따라 평가되어야 합니다.
1) 회수율이 80 % 이상이어야 합니다.
2) 오 탐률이 10 % 이하이어야 합니다.
3) 비즈니스 비용을 최소화해야 합니다.
각 이진 분류 모델을 생성 한 후 데이터 과학자는 해당 혼동 행렬을 생성합니다.
요구 사항을 충족하는 모델을 나타내는 혼동 행렬은 무엇입니까?
A. TN = 96, FP = 4
FN = 10, TP = 90
B. TN = 98, FP = 2
FN = 18, TP = 82
C. TN = 91, FP = 9
FN = 22, TP = 78
D. TN = 99, FP = 1
FN = 21, TP = 79
Answer: B
Explanation:
The following calculations are required:
TP = True Positive
FP = False Positive
FN = False Negative
TN = True Negative
FN = False Negative
Recall = TP / (TP + FN)
False Positive Rate (FPR) = FP / (FP + TN)
Cost = 5 * FP + FN

Options C and D have a recall greater than 80% and an FPR less than 10%, but D is the most cost effective.