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NEW QUESTION: 1
You are cabling two Cisco 3232C switches for the cluster interconnect of a 4-node AFF A800 cluster.
Which pair of ports are used to cable the Inter-Switch Link (ISL) between the switches?
A. 1/21 to 1/24
B. 1/31 and 1/32
C. 0/1 and 0/2
D. 0/13 to 0/16
Answer: B

NEW QUESTION: 2
Given:
import java.util.*;
public class SearchText {
public static void main(String[] args) {
Object[] array1 = new Object[3];
array1[0] = "foo";
array1[0] = 1;
array1[0] = 'a';
int index = Arrays.binarySearch(array1, "bar");
System.out.println(index);
}
}
What is the result?
A. Compilation fails
B. 0
C. - 1
D. 1
E. An exception is thrown at runtime
Answer: E
Explanation:
The code compiles fine.
An exception is thrown at runtime due to data type comparison mismatch:
Exception in thread "main" java.lang.ClassCastException: java.lang.String cannot be cast
to java.lang.Integer
at java.lang.Integer.compareTo(Integer.java:52)
at java.util.Arrays.binarySearch0(Arrays.java:1481)
at java.util.Arrays.binarySearch(Arrays.java:1423)
at searchtext.SearchText.main(SearchText.java:22)
Note: binarySearch
public static int binarySearch(char[] a,
char key)
Searches the specified array of chars for the specified value using the binary search
algorithm. The array must be sorted (as by the sort method, above) prior to making this
call. If it is not sorted, the results are undefined. If the array contains multiple elements with
the specified value, there is no guarantee which one will be found.
Parameters:
a - the array to be searched.
key - the value to be searched for.
Returns:
index of the search key, if it is contained in the list; otherwise, (-(insertion point) - 1). The
insertion point is defined as the point at which the key would be inserted into the list: the
index of the first element greater than the key, or list.size(), if all elements in the list are less
than the specified key. Note that this guarantees that the return value will be >= 0 if and
only if the key is found.

NEW QUESTION: 3
Your company has a private cloud that is managed by using a System Center 2012
Operations Manager infrastructure.
The Operations Manager management server role is installed on a server named Server1.
You deploy a server named Server2, and then join Server2 to the domain.
You log on to Server2 and install the Operations Manager agent. You specify Server1 as
the management server.
You notice that Server1 did not discover Server2.
You need to add Server2 as an agent-managed device.
What should you do from the Operations Manager console?
A. Modify the Global Management Server Settings - Security settings.
B. Create a new discovery rule.
C. Import the Windows Servers Base Operating System Management Pack.
D. Run the Discovery Wizard - Computer and Device Management Wizard.
Answer: A
Explanation:
System Center Operations Manager 2012: Discovery http://onetechday.wordpress.com/2012/04/28/system-center-operations-manager-2012discovery/ Windows Servers Base Operating System Management Pack: http://www.microsoft.com/en-us/download/details.aspx?id=20630 outdated MP for Windows 2000, Windows NT, Windows Server 2003, Windows XP Most likely not the solution, although possible.
Solution should be:We did a manual Agent install http://technet.microsoft.com/en-us/library/hh212853.aspx To configure manual agent installation settings for management group 1.Log on to the Operations console with an account that is a member of the Operations Manager Administrators role.
2.Click Administration.
3.In the Administration workspace, expand Administration, and then click Settings.
4.In the Settings pane, expand Type: Server, right-click Security, and then click Properties.
5.In the Global Management Server Settings - Security dialog box, on the General tab, do
one of the following:
To maintain a higher level of security, click Reject new manual agent installations, and then
click OK.
To configure for manual agent installation, click Review new manual agent installations in
pending management view, and then click OK.
Optionally, select Auto-approve new manually installed agents.