Fortinet NSE5_FCT-7.0 dumps - in .pdf

NSE5_FCT-7.0 pdf
  • Exam Code: NSE5_FCT-7.0
  • Exam Name: Fortinet NSE 5 - FortiClient EMS 7.0
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • PDF Price: $51.98

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  • Exam Code: NSE5_FCT-7.0
  • Exam Name: Fortinet NSE 5 - FortiClient EMS 7.0
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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NSE5_FCT-7.0 Testing Engine
  • Exam Code: NSE5_FCT-7.0
  • Exam Name: Fortinet NSE 5 - FortiClient EMS 7.0
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
  • Testing Engine

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NEW QUESTION: 1
Which three statements are true about WebLogic clusters? (Choose three.)
A. All cluster members must bind to the same port number.
B. Web applications require a proxy in order to be used in a cluster.
C. Clusters provide clients with transparent failover.
D. Cluster members replicate application data by using heartbeats.
E. EJB applications can be targeted to entire cluster.
F. Cluster members can be associated with one or more domains.
Answer: B,C,E

NEW QUESTION: 2
When considering key structure, which three options are mutually exclusive? (Choose three.)
A. Alternate Search Key
B. Descending Key
C. Duplicate Order Key
D. Search Key
E. Key
Answer: A,C,E

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c INNER JOIN (SELECT
CustomerID, ShippingCountry,COUNT(OrderAmount) DESC)
AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry)
AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK()OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN (SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders GROUP BY CustomerID, ShippingCountry)
AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN (SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1
Incorrect Answers:
B: The ascending (ASC) sorting would produce the country from which each customer has placed the least orders.
C: We are interested in the number of the orders, not the amount of the orders. We should use ORDER BY COUNT(OrderAmount), not ORDER BY OrderAmount.
D: We are only interested in one single post, only the country from which each customer has placed the most orders. Need to use a WHERE statement (here Where o.Rnk =1 ).

NEW QUESTION: 4
Which statement describes the Mobile First user experience?
A. Unified exchange is now available on mobile devices like smartphones and tablets.
B. A mobile device like a smartphone or tablet will be updated with Presence information first.
C. The Client interface experience has been optimized for mobile devices such as smartphones and tablets.
D. When two Clients register, the mobile Client gets priority over non-mobile devices.
Answer: C

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