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NEW QUESTION: 1
Which of the following technologies use tunnels to allow for communication between devices with IPv6 addresses?
A. 6to4
B. ISATAP
C. Dual Stack
D. NAT64
Answer: A

NEW QUESTION: 2
What is the purpose of the catalog command?
A. To create metadata in the control file and the recovery catalog related to backup set pieces
B. To review RMAN control file and recovery catalog metadata and ensure that it's correct
C. To create a report that lists database backups
D. To delete RMAN backup-related metadata from the recovery catalog
E. To rebuild the recovery catalog
Answer: A

NEW QUESTION: 3
Which of the following is an SAP Ariba best practice that is specific to the SAP Ariba Supplier Performance Management (SPM) project template?
A. Create a template question to clarify the recurrence cycle of the evaluation period.
B. Build a Team Member Rules file to determine SPM project members.
C. Upload and prepare necessary SPM project documents.
D. Add survey content.
Answer: B

NEW QUESTION: 4
View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables.
You need to create a view that displays the ORDER ID, ORDER_DATE, and the total number of
items in each order.
Which CREATE VIEW statement would create the view successfully?

A. CREATE OR REPLACE VIEW ord_vu (order_id,order_date)
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
B. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
C. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)| NO OF ITEMS'
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date
WITH CHECK OPTION;
D. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
Answer: B