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C_CPI_2404 pdf
  • Exam Code: C_CPI_2404
  • Exam Name: SAP Certified Associate - Integration Developer
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • PDF Price: $51.98

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  • Exam Code: C_CPI_2404
  • Exam Name: SAP Certified Associate - Integration Developer
  • Version: V17.95
  • Q & A: 400 Questions and Answers
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  • Exam Code: C_CPI_2404
  • Exam Name: SAP Certified Associate - Integration Developer
  • Version: V17.95
  • Q & A: 400 Questions and Answers
  • Software Price: $51.98
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NEW QUESTION: 1
The primary organ for drug elimination is the:
A. lung(s).
B. liver.
C. skin.
D. kidney(s).
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Most drugs are excreted in the urine, either as the parent compound or as drug metabolites. Relatively few drugs are excreted in sweat. Some volatile gases are excreted with expiration. The liver primarily metabolizes drugs. Some of them are excreted in bile, especially those with a molecular weight above 300.
Pharmacological Therapies

NEW QUESTION: 2

What do the buttons in the red box do?
A. They can be used to filter events from being transmitted when playing the song.
B. They can be used to filter events from being displayed in the editor.
C. They can be used to filter events from being recorded.
Answer: B

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out<<val<<" ";
}
};
struct Sequence {
int start;
Sequence(int start):start(start){}
int operator()() { return start++; } };
int main() {
vector<int> v1(10);
vector<int> v2(10);
generate(v1.begin(), v1.end(), Sequence(1));
random(v1.begin(),v1.end());
for_each(v1.begin(), v1.end(), Out<int>(cout) );cout<<endl;
return 0;
}
Program outputs:
A. 8 2 4 9 5 7 10 6 1 3
B. compilation error
C. 10 9 8 7 6 5 4 3 2 1
D. 1 2 3 4 5 6 7 8 9 10
Answer: B

NEW QUESTION: 4
-- Exhibit -user@R1> show ospf neighbor Address Interface State ID Pri Dead
10.222.0.2 ge-0/0/1.0 Init 10.222.1.2 128 32
user@R1> show ospf interface detail Interface State Area DR ID BDR ID Nbrs ge-0/0/1.0 DR 0.0.0.0 10.222.1.1 0.0.0.0 1
Type: LAN, Address: 10.222.0.1, Mask: 255.255.255.252, MTU: 1500, Cost: 1
DR addr: 10.222.0.1, Priority: 128 Adj count: 0 Hello: 10, DeaD. 40, ReXmit: 5, Not Stub Auth type: MD5, Active key ID. 10, Start time: 1970 Jan 1 00:00:00 UTC Protection type: None Topology default (ID 0) -> Cost: 1
lo0.0 DR 0.0.0.0 10.222.1.1 0.0.0.0 0 Type: LAN, Address: 10.222.1.1, Mask: 255.255.255.255, MTU: 65535, Cost: 0 DR addr: 10.222.1.1, Priority: 128 Adj count: 0 Hello: 10, DeaD. 40, ReXmit: 5, Not Stub Auth type: None Protection type: None Topology default (ID 0) -> Cost: 0
user@R2> show ospf neighbor
user@R2> show ospf interface detail Interface State Area DR ID BDR ID Nbrs ge-0/0/1.0 PtToPt 0.0.0.0 0.0.0.0 0.0.0.0 0
Type: P2P, Address: 10.222.0.2, Mask: 255.255.255.252, MTU: 1500, Cost: 1 Adj count: 0 Hello: 10, DeaD. 40, ReXmit: 5, Not Stub Auth type: MD5, Active key ID. 10, Start time: 1970 Jan 1 00:00:00 UTC Protection type: None Topology default (ID 0) -> Cost: 1
lo0.0 DR 0.0.0.0 10.222.1.2 0.0.0.0 0 Type: LAN, Address: 10.222.1.2, Mask: 255.255.255.255, MTU: 65535, Cost: 0 DR addr: 10.222.1.2, Priority: 128 Adj count: 0 Hello: 10, DeaD. 40, ReXmit: 5, Not Stub Auth type: None Protection type: None Topology default (ID 0) -> Cost: 0
-- Exhibit -
Click the Exhibit button.
You are trying to establish an OSPF adjacency between R1 and R2, but the adjacency does not establish.
Referring to the exhibit, what is causing the adjacency to fail?
A. The MD5 key ID values are mismatched between R1 and R2.
B. The interface type is mismatched between R1 and R2.
C. The IP subnet mask is mismatched between R1 and R2.
D. R1 has both family inet and family iso configured on the link toward R2.
Answer: B

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