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NEW QUESTION: 1
Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some question sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
Your company is deploying an on-premises application named Appl. Users will access App1 by using a URL of https://app1.contoso.com. You register App1 in Azure Active Directory (Azure AD) and publish Appl by using the Azure AD Application Proxy. You need to ensure that Appl appears in the My Apps portal for all the users.
Solution: You create an offer for App1 and publish the offer to Azure Marketplace.
A. Yes
B. No
Answer: A

NEW QUESTION: 2
사기로 의심되는 개인을 심문하는 데 사용되는 질문은 다음과 같아야 합니다.
A. 둘 이상의 주제 또는 주제를 다룹니다.
B. 개인을 원하는 답변으로 안내합니다.
C. 일반에서 특정으로 이동하십시오.
D. 미리 정해진 순서를 준수하십시오.
Answer: C

NEW QUESTION: 3
다음 중 프로젝트 관리자가 권한 수준과 관심 수준에 따라 이해 관계자를 그룹화하는 데 사용할 수 있는 것은 무엇입니까?
A. 전력 / 영향 그리드
B. 영향 / 충격 그리드
C. Salience 모델
D. 전력 /이자 그리드
Answer: D

NEW QUESTION: 4
You have a Microsoft SQL Server 2012 database that contains tables named Customers and Orders.
The tables are related by a column named CustomerID.
You need to create a query that meets the following requirements:
- Returns the CustomerName for all customers and the OrderDate for any orders that they have placed. - Results must include customers who have not placed any orders.
Which Transact-SQL query should you use?
A. SELECT CustomerName, CrderDate FROM Customers JOIN Orders ON Customers.CustomerID = Orders.CustomerID
B. SELECT CustomerName, OrderDate FROM Customers LEFT OUTER JOIN Orders ON Customers.CustomerID = Orders.CustomerID
C. SELECT CustomerName, OrderDate FROM Customers RIGHT OUTER JOIN Orders ON Customers.CustomerID = Orders.CustomerID
D. SELECT CustomerName, OrderDate FROM Customers CROSS JOIN Orders ON Customers.CustomerID = Orders.CustomerID
Answer: B
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms177634.aspx