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  • Vendor : OMG
  • Certifications : OMG Certification
  • Exam Name : OMG Certified UML Professional 2 (OCUP 2) - Foundation Level
  • Exam Code : OMG-OCUP2-FOUND100
  • Total Questions : 376 Q&As
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What is VCE Simulator?
VCE Exam Simulator is a test engine designed specifically for certification exam preparation. It allows you to create, edit, and take practice tests in an environment very similar to an actual exam.
SKU: OMG-OCUP2-FOUND100 Categories: ,

Description

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    NEW QUESTION: 1
    Which of the following is the default port for POP3?
    A. 0
    B. 1
    C. 2
    D. 3
    Answer: C

    NEW QUESTION: 2
    Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
    You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

    You need to run a query to find the total number of customers who have both deposit and loan accounts.
    Which Transact-SQL statement should you run?
    A. SELECT COUNT(*)
    FROM (SELECT CustNo
    FROM tblDepositAcct
    UNION
    SELECT CustNo
    FROM tblLoanAcct) R
    B. SELECT COUNT(*)
    FROM tblDepositAcct D
    FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
    C. SELECT COUNT(*)
    FROM (SELECT CustNo
    FROM tblDepositAcct
    EXCEPT
    SELECT CustNo
    FROM tblLoanAcct) R
    D. SELECT COUNT(*)
    FROM (SELECT AcctNo
    FROM tblDepositAcct
    INTERSECT
    SELECT AcctNo
    FROM tblLoanAcct) R
    E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
    FROM tblDepositAcct D
    FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
    WHERE D.CustNo IS NULL OR L.CustNo IS NULL
    F. SELECT COUNT(DISTINCT L.CustNo)
    FROM tblDepositAcct D
    RIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNo
    WHERE D.CustNo IS NULL
    G. SELECT COUNT(*)
    FROM (SELECT CustNo
    FROM tblDepositAcct
    UNION ALL
    SELECT CustNo
    FROM tblLoanAcct) R
    H. SELECT COUNT (DISTINCT D.CustNo)
    FROM tblDepositAcctD, tblLoanAcct L
    WHERE D.CustNo = L.CustNo
    Answer: D
    Explanation:
    Explanation/Reference:
    Explanation:
    The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
    References: https://www.techonthenet.com/sql/intersect.php

    NEW QUESTION: 3
    DRAG DROP
    Your network contains four servers that run Windows Server 2012 R2.
    Each server has the Failover Clustering feature installed. Each server has three network adapters installed. An iSCSI SAN is available on the network.
    You create a failover cluster named Cluster1. You add the servers to the cluster.
    You plan to configure the network settings of each server node as shown in the following table.

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    What should you do?
    To answer, drag the appropriate network communication setting to the correct cluster network. Each network communication setting may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
    Select and Place:

    Answer:
    Explanation:

    Explanation/Reference:
    Explanation:
    Allow cluster network communication for heartbeats.
    Note: Heartbeats
    The Cluster service, running on each node of the cluster, keeps track of the current state of the nodes within a cluster and determines when a group and its resources fail over to an alternate node. This communication takes the form of messages that are sent regularly between each node's Cluster service.
    These messages are called heartbeats.
    Reference: Network communication between nodes
    http://technet.microsoft.com/en-us/library/cc787135(v=WS.10).aspx

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    A. Length
    B. Acct-session-ID
    C. State
    D. Identifier
    E. Calling-station-ID
    F. Authenticator
    Answer: B,C,E


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